In the data set below, what is the standard deviation?

2 9 8 2 6 3 5
If the answer is a decimal, round it to the nearest tenth.

standard deviation (σ):

1 answer

To calculate the standard deviation of the data set \( 2, 9, 8, 2, 6, 3, 5 \), we can follow these steps:

  1. Calculate the mean (average) of the data set.
  2. Calculate the squared deviations from the mean.
  3. Calculate the variance (which is the average of the squared deviations).
  4. Take the square root of the variance to find the standard deviation.

Step 1: Calculate the mean

\[ \text{Mean} = \frac{\sum \text{data}}{n} = \frac{2 + 9 + 8 + 2 + 6 + 3 + 5}{7} = \frac{35}{7} = 5 \]

Step 2: Calculate the squared deviations from the mean

\[ (2 - 5)^2 = (-3)^2 = 9 \] \[ (9 - 5)^2 = (4)^2 = 16 \] \[ (8 - 5)^2 = (3)^2 = 9 \] \[ (2 - 5)^2 = (-3)^2 = 9 \] \[ (6 - 5)^2 = (1)^2 = 1 \] \[ (3 - 5)^2 = (-2)^2 = 4 \] \[ (5 - 5)^2 = (0)^2 = 0 \]

Step 3: Calculate the variance

Now we sum up the squared deviations: \[ 9 + 16 + 9 + 9 + 1 + 4 + 0 = 48 \] Now divide by the number of data points (since this is a population standard deviation): \[ \text{Variance} = \frac{48}{7} \approx 6.8571 \]

Step 4: Calculate the standard deviation

\[ \sigma = \sqrt{\text{Variance}} = \sqrt{6.8571} \approx 2.617 \]

Final result

Rounding to the nearest tenth, the standard deviation \( \sigma \) is approximately: \[ \text{Standard deviation } (\sigma) \approx 2.6 \]

Thus, the final answer is: \[ \boxed{2.6} \]