Question
Lisa bought a refrigerator that measures 76cm x 76cm x170cm to fit in a space with a volume of 975,000 cubic cm. Will the refrigerator fit in the space?
Yes
No
Yes
No
Answers
GPT-4o mini
To determine if the refrigerator can fit in the space, we first need to calculate the volume of the refrigerator.
The dimensions of the refrigerator are:
- Length: 76 cm
- Width: 76 cm
- Height: 170 cm
The volume of the refrigerator can be calculated using the formula for the volume of a rectangular prism:
\[
\text{Volume} = \text{Length} \times \text{Width} \times \text{Height}
\]
Substituting in the dimensions:
\[
\text{Volume} = 76 \, \text{cm} \times 76 \, \text{cm} \times 170 \, \text{cm}
\]
Calculating this step-by-step:
1. Calculate \( 76 \times 76 = 5776 \, \text{cm}^2 \)
2. Calculate \( 5776 \times 170 = 982720 \, \text{cm}^3 \)
Now we can compare the volume of the refrigerator (\( 982720 \, \text{cm}^3 \)) to the volume of the space (\( 975000 \, \text{cm}^3 \)):
Since \( 982720 \, \text{cm}^3 \) (the volume of the refrigerator) is greater than \( 975000 \, \text{cm}^3 \) (the volume of the space), we conclude that the refrigerator will not fit in the space.
Therefore, the answer is **No**.
The dimensions of the refrigerator are:
- Length: 76 cm
- Width: 76 cm
- Height: 170 cm
The volume of the refrigerator can be calculated using the formula for the volume of a rectangular prism:
\[
\text{Volume} = \text{Length} \times \text{Width} \times \text{Height}
\]
Substituting in the dimensions:
\[
\text{Volume} = 76 \, \text{cm} \times 76 \, \text{cm} \times 170 \, \text{cm}
\]
Calculating this step-by-step:
1. Calculate \( 76 \times 76 = 5776 \, \text{cm}^2 \)
2. Calculate \( 5776 \times 170 = 982720 \, \text{cm}^3 \)
Now we can compare the volume of the refrigerator (\( 982720 \, \text{cm}^3 \)) to the volume of the space (\( 975000 \, \text{cm}^3 \)):
Since \( 982720 \, \text{cm}^3 \) (the volume of the refrigerator) is greater than \( 975000 \, \text{cm}^3 \) (the volume of the space), we conclude that the refrigerator will not fit in the space.
Therefore, the answer is **No**.