Question
Write the total ionic and net ionic equation, consider the balance equation as well as stage for NaOH(aq)+CO2(g)produce Na2CO3(aq)+H2O(l)
Answers
GPT-4o mini
To write the total ionic and net ionic equations for the reaction between sodium hydroxide (NaOH) and carbon dioxide (CO₂) to produce sodium carbonate (Na₂CO₃) and water (H₂O), we first need to start with the balanced molecular equation.
### Step 1: Write the balanced molecular equation
The balanced equation for the reaction is:
\[ 2 \, \text{NaOH (aq)} + \text{CO}_2 \, \text{(g)} \rightarrow \text{Na}_2\text{CO}_3 \, \text{(aq)} + \, \text{H}_2\text{O (l)} \]
### Step 2: Write the total ionic equation
Next, we can break down the soluble ionic compounds into their respective ions. Since NaOH and Na₂CO₃ are soluble in water, they will dissociate into their ions, while CO₂ will not dissociate.
The total ionic equation is:
\[ 2 \, \text{Na}^+ \, (aq) + 2 \, \text{OH}^- \, (aq) + \text{CO}_2 \, (g) \rightarrow 2 \, \text{Na}^+ \, (aq) + \text{CO}_3^{2-} \, (aq) + \text{H}_2\text{O} \, (l) \]
### Step 3: Write the net ionic equation
To obtain the net ionic equation, we can eliminate the spectator ions (ions that appear on both sides of the total ionic equation without undergoing any change). In this case, sodium ions (Na⁺) are spectator ions.
Removing the Na⁺ ions, we get:
\[ 2 \, \text{OH}^- \, (aq) + \text{CO}_2 \, (g) \rightarrow \text{CO}_3^{2-} \, (aq) + \text{H}_2\text{O} \, (l) \]
This is the net ionic equation for the reaction between sodium hydroxide and carbon dioxide.
### Summary
- **Balanced Molecular Equation**:
\[ 2 \, \text{NaOH (aq)} + \text{CO}_2 \, \text{(g)} \rightarrow \text{Na}_2\text{CO}_3 \, \text{(aq)} + \, \text{H}_2\text{O (l)} \]
- **Total Ionic Equation**:
\[ 2 \, \text{Na}^+ \, (aq) + 2 \, \text{OH}^- \, (aq) + \text{CO}_2 \, (g) \rightarrow 2 \, \text{Na}^+ \, (aq) + \text{CO}_3^{2-} \, (aq) + \text{H}_2\text{O} \, (l) \]
- **Net Ionic Equation**:
\[ 2 \, \text{OH}^- \, (aq) + \text{CO}_2 \, (g) \rightarrow \text{CO}_3^{2-} \, (aq) + \text{H}_2\text{O} \, (l) \]
### Step 1: Write the balanced molecular equation
The balanced equation for the reaction is:
\[ 2 \, \text{NaOH (aq)} + \text{CO}_2 \, \text{(g)} \rightarrow \text{Na}_2\text{CO}_3 \, \text{(aq)} + \, \text{H}_2\text{O (l)} \]
### Step 2: Write the total ionic equation
Next, we can break down the soluble ionic compounds into their respective ions. Since NaOH and Na₂CO₃ are soluble in water, they will dissociate into their ions, while CO₂ will not dissociate.
The total ionic equation is:
\[ 2 \, \text{Na}^+ \, (aq) + 2 \, \text{OH}^- \, (aq) + \text{CO}_2 \, (g) \rightarrow 2 \, \text{Na}^+ \, (aq) + \text{CO}_3^{2-} \, (aq) + \text{H}_2\text{O} \, (l) \]
### Step 3: Write the net ionic equation
To obtain the net ionic equation, we can eliminate the spectator ions (ions that appear on both sides of the total ionic equation without undergoing any change). In this case, sodium ions (Na⁺) are spectator ions.
Removing the Na⁺ ions, we get:
\[ 2 \, \text{OH}^- \, (aq) + \text{CO}_2 \, (g) \rightarrow \text{CO}_3^{2-} \, (aq) + \text{H}_2\text{O} \, (l) \]
This is the net ionic equation for the reaction between sodium hydroxide and carbon dioxide.
### Summary
- **Balanced Molecular Equation**:
\[ 2 \, \text{NaOH (aq)} + \text{CO}_2 \, \text{(g)} \rightarrow \text{Na}_2\text{CO}_3 \, \text{(aq)} + \, \text{H}_2\text{O (l)} \]
- **Total Ionic Equation**:
\[ 2 \, \text{Na}^+ \, (aq) + 2 \, \text{OH}^- \, (aq) + \text{CO}_2 \, (g) \rightarrow 2 \, \text{Na}^+ \, (aq) + \text{CO}_3^{2-} \, (aq) + \text{H}_2\text{O} \, (l) \]
- **Net Ionic Equation**:
\[ 2 \, \text{OH}^- \, (aq) + \text{CO}_2 \, (g) \rightarrow \text{CO}_3^{2-} \, (aq) + \text{H}_2\text{O} \, (l) \]