Rewrite the irrational cube root 189 −−−3√ as the product of an integer and another irrational cube root

1 answer

To rewrite the irrational cube root \( \sqrt[3]{189} \) as the product of an integer and another cube root, we can first factor 189.

The prime factorization of 189 is:

\[ 189 = 3^3 \times 7 \]

Now, we can separate the cube root:

\[ \sqrt[3]{189} = \sqrt[3]{3^3 \times 7} \]

This can be split into two parts:

\[ \sqrt[3]{189} = \sqrt[3]{3^3} \times \sqrt[3]{7} \]

Since \( \sqrt[3]{3^3} = 3 \), we have:

\[ \sqrt[3]{189} = 3 \times \sqrt[3]{7} \]

Thus, \( \sqrt[3]{189} \) can be rewritten as:

\[ 3 \sqrt[3]{7} \]