To compare the functions \( f(x) = 8x \) and \( g(x) = \log_8 x \), we first evaluate the second function \( g(x) \) at the points provided for \( f(x) \).
The function \( g(x) = \log_8 x \) means we will find the logarithm of \( x \) with base 8.
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For \( f(1) = 8 \): \[ g(8) = \log_8 8 = 1 \] So, the point \( (8, 1) \) is on the graph of \( g(x) \).
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For \( f(-1) \): The value \( x = -1 \) is not in the domain of \( g(x) \) because the logarithm function is undefined for negative numbers. Therefore, we cannot find \( g(-1) \).
Now let’s look through the provided options to find valid points for \( g(x) \):
- (−1,−8) and (1,−0.125): Invalid as \( g(-1) \) is undefined, but \( g(1) = 0 \).
- (1,0.125) and (−1,8): \( g(1) = 0 \) which is valid, but \( g(-1) \) is still invalid.
- (8,1) and (0.125,−1): \( g(8) = 1 \) is valid, and \( g(0.125) = \log_8(0.125) = \log_8(8^{-1}) = -1\), which is also valid.
- (1,8) and (−1,0.125): Invalid, \( g(1) = 0 \) and \( g(-1) \) is undefined.
Therefore, the two valid points for the graph of \( g(x) \) are: (8, 1) and (0.125, -1).
So the correct answer is: (8,1) and (0.125,−1).