To find the volume of a rectangular prism (like a moving truck), you can use the formula:
\[ \text{Volume} = \text{length} \times \text{width} \times \text{height} \]
Given:
- Length = 9910 ft
- Width = 6910 ft
- Height = 6110 ft
Now, calculate the volume:
\[ \text{Volume} = 9910 , \text{ft} \times 6910 , \text{ft} \times 6110 , \text{ft} \]
Calculating step by step:
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First, calculate \( 9910 \times 6910 \):
- \( 9910 \times 6910 = 68539990 \)
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Now, take that result and multiply it by 6110:
- \( 68539990 \times 6110 = 418254330900 \)
So, the volume of the moving truck is:
\[ \text{Volume} = 418254330900 , \text{ft}^3 \]
None of the options seem to match this directly. Let's explore if I made a mistake in reading the numbers or if there's a different interpretation.
If your measurements are given in incorrect formats (like adding extra zeros), then please ensure they are correctly listed as lengths typically do not exceed 100ft in regular moving trucks.
If you meant the measurements were something like 99.10 ft long, 61.10 ft high, and 69.10 ft wide, we would do:
\[ 99.10 , \text{ft} \times 69.10 , \text{ft} \times 61.10 , \text{ft} \]
- First calculate \( 99.10 \times 69.10 = 6859.81 \)
- Now multiply that by \( 61.10 \):
- \( 6859.81 \times 61.10 \approx 418254.30 , \text{ft}^3 \)
This result would be \( 418254.30 \) ft³ or \( 418 \cdot \frac{2543}{10000} \) which is also not on the list.
Clearly, I suggest rechecking what the actual sizes you're working with should be if none of these calculations line up with the options provided!