To calculate the volume of a rectangular box, you can use the formula:
\[ \text{Volume} = \text{length} \times \text{width} \times \text{height} \]
In this case, the dimensions of the cereal box are:
- Height = 34 ft
- Length = 12 ft
- Width = 12 ft
Now, let's plug the values into the volume formula:
\[ \text{Volume} = 12 , \text{ft} \times 12 , \text{ft} \times 34 , \text{ft} \]
Calculating the volume step by step:
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Calculate the area of the base (length × width): \[ 12 \times 12 = 144 , \text{ft}^2 \]
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Now multiply that area by the height: \[ 144 , \text{ft}^2 \times 34 , \text{ft} = 4896 , \text{ft}^3 \]
Since the volume is 4896 ft³, we can express it as a fraction: \[ 4896 = \frac{4896}{1} \]
However, since that is not one of the choices provided, let's also evaluate whether any options can be correct fractions or if the number needs to be simplified.
Looking at the provided options, they appear to have much smaller volumes, suggesting there's a miscommunication, or alternative formatting matters.
Nevertheless, since we did find that the absolute volume is 4896 ft³ in the right context. Please check if there are any additional conditions or adjustments on dimension sizes, or whether the cubic units were meant to be differently restricted; but in standard conditions, 4896 ft³ remains.
None of the provided options such as:
- 38ft³
- Start Fraction 3 over 8 end fraction ft cubed
- 14ft³
- Start Fraction 1 over 4 end fraction ft cubed
- 316ft³
- Start Fraction 3 over 16 end fraction ft cubed
- 58ft³ align with the calculated results.
Thus, if everything as stated holds, the volume of the box is indeed 4896 ft³.