To calculate the median of the original dataset and then the new dataset after adding Michael's pair of shoes, we will follow these steps:
1. Original Dataset
The original data collected by Michael is as follows:
- 2 pairs: 5 students
- 3 pairs: 6 students
- 4 pairs: 1 student
- 5 pairs: 1 student
- 6 pairs: 4 students
- 7 pairs: 7 students
- 8 pairs: 2 students
- 10 pairs: 1 student
Let's list out the number of pairs of shoes owned by each student:
- From "2 pairs: 5 students", we have: 2, 2, 2, 2, 2
- From "3 pairs: 6 students", we have: 3, 3, 3, 3, 3, 3
- From "4 pairs: 1 student", we have: 4
- From "5 pairs: 1 student", we have: 5
- From "6 pairs: 4 students", we have: 6, 6, 6, 6
- From "7 pairs: 7 students", we have: 7, 7, 7, 7, 7, 7, 7
- From "8 pairs: 2 students", we have: 8, 8
- From "10 pairs: 1 student", we have: 10
Now, let's list out all the numbers: \[ 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 4, 5, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 7, 8, 8, 10 \]
2. Finding the Median of the Original Dataset
There are 27 (5 + 6 + 1 + 1 + 4 + 7 + 2 + 1) students. Since 27 is odd, the median will be the middle number, which is the 14th number in the ordered list.
Counting through the listed pairs, we find the 14th number:
- \(2, 2, 2, 2, 2\) (5 values)
- \(3, 3, 3, 3, 3, 3\) (6 values) = 11 values total
- \(4\) (1 value) = 12 values total
- \(5\) (1 value) = 13 values total
- \(6\) (4 values) = 17 values total
The 14th number is \(6\).
3. New Dataset (Including Michael)
We add Michael's 4 pairs of shoes: \[ 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 4, 4, 5, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 7, 8, 8, 10 \]
Now, there are 28 students. Since 28 is even, the median is the average of the two middle numbers (14th and 15th).
Counting through the new ordered list:
- The 14th number is \(5\).
- The 15th number is \(6\).
4. Calculate the Median of the New Dataset
\[ \text{Median} = \frac{5 + 6}{2} = \frac{11}{2} = 5.5 \]
Final Answers:
- Median of the original dataset: 6
- Median of the new dataset (with Michael): 5.5