To solve for the vertical intercept \( b \) in the equation \( y = mx + b \), we first need to identify the slope \( m \) of the line using the given points. We have two points: \( (4, 60) \) and \( (2, 40) \).
- Calculate the slope \( m \) using the formula:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
Using the points \( (x_1, y_1) = (2, 40) \) and \( (x_2, y_2) = (4, 60) \):
\[ m = \frac{60 - 40}{4 - 2} = \frac{20}{2} = 10 \]
Now that we have the slope \( m \), we can use one of the points to calculate the intercept \( b \). We can use the point \( (2, 40) \):
- Plug the point \( (2, 40) \) into the equation \( y = mx + b \):
\[ 40 = 10(2) + b \] \[ 40 = 20 + b \]
- Solve for \( b \):
\[ b = 40 - 20 = 20 \]
Thus, the vertical intercept \( b \) is:
\[ \boxed{20} \]