Given A(−1,2)

and B(3,6)
, find the coordinates of point X
on AB¯¯¯¯¯¯¯¯
such that the ratio of AX
to XB
is 3:5.(1 point)
Responses

(−14,312)
Start Fraction 3 over 2 End Fraction

(12,312)
Start Fraction 2 over 3 End Fraction

(112,112)
Start Fraction 2 over 1 End Fraction

(125,425)

1 answer

To find the coordinates of point \( X \) on line segment \( \overline{AB} \) such that the ratio of \( AX \) to \( XB \) is \( 3:5 \), we first need to determine the position of point \( X \) along the line segment defined by points \( A(-1, 2) \) and \( B(3, 6) \).

Using the section formula, we can find the coordinates of point \( X \) dividing \( AB \) in the ratio \( m:n = 3:5 \). The coordinates \( (x, y) \) of point \( X \) can be calculated as follows:

\[ x = \frac{m \cdot x_2 + n \cdot x_1}{m+n} \] \[ y = \frac{m \cdot y_2 + n \cdot y_1}{m+n} \]

Where:

  • \( A(x_1, y_1) = (-1, 2) \)
  • \( B(x_2, y_2) = (3, 6) \)
  • \( m = 3 \) (part of ratio towards point \( B \))
  • \( n = 5 \) (part of ratio towards point \( A \))

Substituting the values:

For x-coordinate: \[ x = \frac{3 \cdot 3 + 5 \cdot (-1)}{3 + 5} = \frac{9 - 5}{8} = \frac{4}{8} = \frac{1}{2} \]

For y-coordinate: \[ y = \frac{3 \cdot 6 + 5 \cdot 2}{3 + 5} = \frac{18 + 10}{8} = \frac{28}{8} = \frac{7}{2} \]

Thus, the coordinates of point \( X \) are: \[ X\left(\frac{1}{2}, \frac{7}{2}\right) \]

Now, we compare these coordinates to the given responses:

  • (−14,312)
  • (12,312)
  • (112,112)
  • (125,425)

None of the given options directly match the calculated coordinates, \( \left(\frac{1}{2}, \frac{7}{2}\right) \).

The correct coordinates for point \( X \) dividing \( \overline{AB} \) in the ratio \( 3:5 \) are:

\[ \boxed{\left(\frac{1}{2}, \frac{7}{2}\right)} \]