Asked by layth

if x.y=30
and x+y=10.3
what is x ?
Answered by bobpursley
xy=30
(10.3-y)y=30
y^2-10.3y+30=0
Use the quadratic equation.
Notice the serd: b^2-4ac is negative, so there are no real solutions.

I wonder if you meant x/y=30
orx=30y

30y+y=10.3
y=10.3/31
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