Question
Rewrite the following polynomial in standard form.
2, minus, 8, x, minus, start fraction, x, squared, divided by, 5, end fraction
2−8x−
5
x
2
2, minus, 8, x, minus, start fraction, x, squared, divided by, 5, end fraction
2−8x−
5
x
2
Answers
GPT-4o mini
To rewrite the polynomial \( 2 - 8x - \frac{x^2}{5} \) in standard form, we need to arrange the terms in descending order of their degree.
The standard form is typically written as:
\[
ax^n + bx^{n-1} + cx^{n-2} + \ldots + k
\]
where \( a, b, c, \ldots \) are coefficients and \( n \) is a non-negative integer indicating the degree of the polynomial.
In this case, we have:
- The term with the highest degree is \(-\frac{x^2}{5}\).
- The linear term is \(-8x\).
- The constant term is \(2\).
Now, we'll rewrite the polynomial:
\[
-\frac{x^2}{5} - 8x + 2
\]
So, the polynomial in standard form is:
\[
-\frac{1}{5}x^2 - 8x + 2
\]
The standard form is typically written as:
\[
ax^n + bx^{n-1} + cx^{n-2} + \ldots + k
\]
where \( a, b, c, \ldots \) are coefficients and \( n \) is a non-negative integer indicating the degree of the polynomial.
In this case, we have:
- The term with the highest degree is \(-\frac{x^2}{5}\).
- The linear term is \(-8x\).
- The constant term is \(2\).
Now, we'll rewrite the polynomial:
\[
-\frac{x^2}{5} - 8x + 2
\]
So, the polynomial in standard form is:
\[
-\frac{1}{5}x^2 - 8x + 2
\]