To find the area of the trapezoid given that the bases are 20 cm and 18 cm, and the height is 8 cm, you can use the formula for the area of a trapezoid:
\[ A = \frac{(B^1 + B^2)}{2} \times H \]
Substituting in the values:
- \(B^1 = 20 , \text{cm}\)
- \(B^2 = 18 , \text{cm}\)
- \(H = 8 , \text{cm}\)
Now, plug in the values:
\[ A = \frac{(20 , \text{cm} + 18 , \text{cm})}{2} \times 8 , \text{cm} \] \[ A = \frac{38 , \text{cm}}{2} \times 8 , \text{cm} \] \[ A = 19 , \text{cm} \times 8 , \text{cm} \] \[ A = 152 , \text{cm}^2 \]
Thus, the area of the trapezoid is:
\[ A = 152 , \text{cm}^2 \]