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The path of a soccer ball can be modeled by the equation h(x)=−12x(x−20) , where h(x) is the height reached by the ball, in fee...Asked by BlUbArRy!2#
                The path of a soccer ball can be modeled by the equation h(x)=−
1
2
 
x(x−20), where h(x) is the height reached by the ball, in feet, and x is the horizontal distance the ball has traveled, in feet. What is the horizontal distance the ball will have traveled when it hits the ground? Use a graph or table if necessary.(1 point)
The ball will have traveled a horizontal distance of
feet when it hits the ground.
            
        1
2
x(x−20), where h(x) is the height reached by the ball, in feet, and x is the horizontal distance the ball has traveled, in feet. What is the horizontal distance the ball will have traveled when it hits the ground? Use a graph or table if necessary.(1 point)
The ball will have traveled a horizontal distance of
feet when it hits the ground.
Answers
                                                    There are no human answers yet.
                                            
                
                    Answered by
            GPT-4o mini
            
    To determine the horizontal distance the ball travels when it hits the ground, we need to find the value of \( x \) when the height \( h(x) \) is equal to 0 (the ground level).
The equation given is:
\[
h(x) = -\frac{1}{2} x(x - 20)
\]
Setting \( h(x) = 0 \):
\[
-\frac{1}{2} x(x - 20) = 0
\]
This equation can be factored as follows:
\[
-\frac{1}{2} x(x - 20) = 0
\]
By setting each factor equal to zero:
1. \( x = 0 \) (This is when the ball is kicked from the ground.)
2. \( x - 20 = 0 \) (This gives \( x = 20 \).)
Thus, when \( x = 20 \) feet, the ball will hit the ground.
The horizontal distance the ball travels when it hits the ground is:
\[
\text{20 feet}
\]
    
The equation given is:
\[
h(x) = -\frac{1}{2} x(x - 20)
\]
Setting \( h(x) = 0 \):
\[
-\frac{1}{2} x(x - 20) = 0
\]
This equation can be factored as follows:
\[
-\frac{1}{2} x(x - 20) = 0
\]
By setting each factor equal to zero:
1. \( x = 0 \) (This is when the ball is kicked from the ground.)
2. \( x - 20 = 0 \) (This gives \( x = 20 \).)
Thus, when \( x = 20 \) feet, the ball will hit the ground.
The horizontal distance the ball travels when it hits the ground is:
\[
\text{20 feet}
\]
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