Charles wants to go on a fishing trip. The price of the excursion varies based on the length of the trip. The line of best fit for these data is y=50x+75, where the price of the trip is based on the number of hours of the trip. What prediction can be made about the length of his trip based on the line of best fit?(1 point)

Responses

Charles can go on a 1-hour fishing trip for less than $100.
Charles can go on a 1-hour fishing trip for less than $100.

Charles pays $300 for a 3-hour trip.
Charles pays $300 for a 3-hour trip.

Charles can take a 6-hour trip for less than $400.
Charles can take a 6-hour trip for less than $400.

For $200, Charles can travel for 2 hours.

1 answer

To analyze the options, we can use the line of best fit equation \( y = 50x + 75 \), where \( y \) is the price of the fishing trip and \( x \) is the number of hours of the trip.

Let's evaluate each statement based on this equation:

  1. Charles can go on a 1-hour fishing trip for less than $100.

    • For \( x = 1 \): \[ y = 50(1) + 75 = 125 \] This means a 1-hour trip costs $125, which is not less than $100.
  2. Charles pays $300 for a 3-hour trip.

    • For \( x = 3 \): \[ y = 50(3) + 75 = 150 + 75 = 225 \] This means a 3-hour trip costs $225, which means he does not pay $300.
  3. Charles can take a 6-hour trip for less than $400.

    • For \( x = 6 \): \[ y = 50(6) + 75 = 300 + 75 = 375 \] A 6-hour trip costs $375, which is less than $400.
  4. For $200, Charles can travel for 2 hours.

    • For \( x = 2 \): \[ y = 50(2) + 75 = 100 + 75 = 175 \] A 2-hour trip costs $175, which is not $200.

Based on this analysis, the only correct statement is: Charles can take a 6-hour trip for less than $400.