Question
Please write the Net Ionic Equation for the reaction of Calcium Chloride and Sodium Carbonate..
Answers
GPT-4o mini
To write the net ionic equation for the reaction between calcium chloride (CaCl₂) and sodium carbonate (Na₂CO₃), we first need to consider the full balanced molecular equation and then break it down into its ionic components.
1. **Write the balanced molecular equation:**
\[
\text{CaCl}_2(aq) + \text{Na}_2\text{CO}_3(aq) \rightarrow \text{CaCO}_3(s) + 2\text{NaCl}(aq)
\]
2. **Dissociate the soluble ionic compounds into their ions:**
- Calcium chloride dissociates into calcium ions and chloride ions:
\[
\text{CaCl}_2(aq) \rightarrow \text{Ca}^{2+}(aq) + 2\text{Cl}^-(aq)
\]
- Sodium carbonate dissociates into sodium ions and carbonate ions:
\[
\text{Na}_2\text{CO}_3(aq) \rightarrow 2\text{Na}^+(aq) + \text{CO}_3^{2-}(aq)
\]
- Sodium chloride is also soluble and dissociates:
\[
2\text{NaCl}(aq) \rightarrow 2\text{Na}^+(aq) + 2\text{Cl}^-(aq)
\]
3. **Write the complete ionic equation:**
\[
\text{Ca}^{2+}(aq) + 2\text{Cl}^-(aq) + 2\text{Na}^+(aq) + \text{CO}_3^{2-}(aq) \rightarrow \text{CaCO}_3(s) + 2\text{Na}^+(aq) + 2\text{Cl}^-(aq)
\]
4. **Cancel out the spectator ions (the ions that appear on both sides):**
The spectator ions in this case are \(2\text{Na}^+\) and \(2\text{Cl}^-\).
5. **Write the net ionic equation:**
After removing the spectator ions, we get the net ionic equation:
\[
\text{Ca}^{2+}(aq) + \text{CO}_3^{2-}(aq) \rightarrow \text{CaCO}_3(s)
\]
This equation represents the formation of solid calcium carbonate from calcium and carbonate ions in solution.
1. **Write the balanced molecular equation:**
\[
\text{CaCl}_2(aq) + \text{Na}_2\text{CO}_3(aq) \rightarrow \text{CaCO}_3(s) + 2\text{NaCl}(aq)
\]
2. **Dissociate the soluble ionic compounds into their ions:**
- Calcium chloride dissociates into calcium ions and chloride ions:
\[
\text{CaCl}_2(aq) \rightarrow \text{Ca}^{2+}(aq) + 2\text{Cl}^-(aq)
\]
- Sodium carbonate dissociates into sodium ions and carbonate ions:
\[
\text{Na}_2\text{CO}_3(aq) \rightarrow 2\text{Na}^+(aq) + \text{CO}_3^{2-}(aq)
\]
- Sodium chloride is also soluble and dissociates:
\[
2\text{NaCl}(aq) \rightarrow 2\text{Na}^+(aq) + 2\text{Cl}^-(aq)
\]
3. **Write the complete ionic equation:**
\[
\text{Ca}^{2+}(aq) + 2\text{Cl}^-(aq) + 2\text{Na}^+(aq) + \text{CO}_3^{2-}(aq) \rightarrow \text{CaCO}_3(s) + 2\text{Na}^+(aq) + 2\text{Cl}^-(aq)
\]
4. **Cancel out the spectator ions (the ions that appear on both sides):**
The spectator ions in this case are \(2\text{Na}^+\) and \(2\text{Cl}^-\).
5. **Write the net ionic equation:**
After removing the spectator ions, we get the net ionic equation:
\[
\text{Ca}^{2+}(aq) + \text{CO}_3^{2-}(aq) \rightarrow \text{CaCO}_3(s)
\]
This equation represents the formation of solid calcium carbonate from calcium and carbonate ions in solution.