A big flower vase has 5 begonias, 6 carnations, and 7 tulips. Two flowers are randomly selected without replacement. What is the probability of selecting two carnations? Express the answer in the simplest form of fraction.(1 point)

1 answer

To determine the probability of selecting two carnations from the flower vase, we first need to find the total number of flowers and then calculate the number of favorable outcomes.

  1. Total number of flowers: \[ \text{Total flowers} = 5 \text{ (begonias)} + 6 \text{ (carnations)} + 7 \text{ (tulips)} = 18 \text{ flowers} \]

  2. Calculating the number of ways to choose 2 carnations:

    • The number of ways to choose 2 carnations from the 6 available is given by the combination formula \( \binom{n}{r} \): \[ \binom{6}{2} = \frac{6!}{2!(6-2)!} = \frac{6 \times 5}{2 \times 1} = 15 \]
  3. Calculating the total number of ways to choose 2 flowers from 18: \[ \binom{18}{2} = \frac{18!}{2!(18-2)!} = \frac{18 \times 17}{2 \times 1} = 153 \]

  4. Calculating the probability of selecting 2 carnations: The probability \( P \) is the number of favorable outcomes over the total outcomes: \[ P(\text{2 carnations}) = \frac{\text{Number of ways to choose 2 carnations}}{\text{Total ways to choose 2 flowers}} = \frac{15}{153} \]

  5. Simplifying the fraction: To simplify \( \frac{15}{153} \), we find the greatest common divisor (GCD) of 15 and 153, which is 3. \[ \frac{15 \div 3}{153 \div 3} = \frac{5}{51} \]

Thus, the probability of selecting two carnations is: \[ \boxed{\frac{5}{51}} \]