Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
If the table below represents a probability model based on observed frequencies, what is the value of x ? This table shows a pr...
If the table below represents a probability model based on observed frequencies, what is the value of x
?
This table shows a probability model for the letters Y, C, A, R, E, and S based on observed frequencies.
Y C A R E S
P(Y) 0.25 0.18 0.30 0.17 x
(1 point)
Responses
0.20
0.20
0.01
0.01
1
1
0.10
?
This table shows a probability model for the letters Y, C, A, R, E, and S based on observed frequencies.
Y C A R E S
P(Y) 0.25 0.18 0.30 0.17 x
(1 point)
Responses
0.20
0.20
0.01
0.01
1
1
0.10
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine the value of \( x \) in the probability model, we need to use the fact that the probabilities should sum to 1. The given probabilities are:
- \( P(Y) = 0.25 \)
- \( P(C) = 0.18 \)
- \( P(A) = 0.30 \)
- \( P(R) = 0.17 \)
- \( P(E) = x \)
- \( P(S) = 1 - (0.25 + 0.18 + 0.30 + 0.17 + x) \) (but we only need the sum of the given probabilities)
First, let's calculate the sum of the known probabilities:
\[
0.25 + 0.18 + 0.30 + 0.17 = 0.90
\]
Since the total probability must equal 1, we can set up the equation:
\[
0.90 + x = 1
\]
To find \( x \), subtract 0.90 from both sides:
\[
x = 1 - 0.90
\]
\[
x = 0.10
\]
Thus, the value of \( x \) is **0.10**.
- \( P(Y) = 0.25 \)
- \( P(C) = 0.18 \)
- \( P(A) = 0.30 \)
- \( P(R) = 0.17 \)
- \( P(E) = x \)
- \( P(S) = 1 - (0.25 + 0.18 + 0.30 + 0.17 + x) \) (but we only need the sum of the given probabilities)
First, let's calculate the sum of the known probabilities:
\[
0.25 + 0.18 + 0.30 + 0.17 = 0.90
\]
Since the total probability must equal 1, we can set up the equation:
\[
0.90 + x = 1
\]
To find \( x \), subtract 0.90 from both sides:
\[
x = 1 - 0.90
\]
\[
x = 0.10
\]
Thus, the value of \( x \) is **0.10**.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.