Question

Terry and bob each have an aquarium is 14 cm long 12 cm high and 10 cm wide. Bobs aquarium is 13 cm long 15 cm high and 8cm wide. Whose aquarium holds the larger volume of water ? How do you know

Answer 1

To determine whose aquarium holds the larger volume of water, we need to calculate the volume of each aquarium using the formula for the volume of a rectangular prism, which is:

\[
\text{Volume} = \text{length} \times \text{height} \times \text{width}
\]

### Terry's Aquarium:
- Length = 14 cm
- Height = 12 cm
- Width = 10 cm

Calculating Terry's volume:

\[
\text{Volume}_{\text{Terry}} = 14 \, \text{cm} \times 12 \, \text{cm} \times 10 \, \text{cm} = 1680 \, \text{cm}^3
\]

### Bob's Aquarium:
- Length = 13 cm
- Height = 15 cm
- Width = 8 cm

Calculating Bob's volume:

\[
\text{Volume}_{\text{Bob}} = 13 \, \text{cm} \times 15 \, \text{cm} \times 8 \, \text{cm} = 1560 \, \text{cm}^3
\]

### Comparison:
- Terry's aquarium volume = 1680 cm³
- Bob's aquarium volume = 1560 cm³

### Conclusion:
Terry's aquarium holds the larger volume of water because 1680 cm³ is greater than 1560 cm³.