Question
Maxs carton has a height if 6 inches with a base area of 12 inches squared. Tuckers carton has a height of 7 inches with a base aea of 10 inches squared. How much more volume does Max's carton have than Tuckers
Answers
GPT-4o mini
To find the volume of each carton, we can use the formula for the volume of a rectangular prism:
\[
\text{Volume} = \text{Base Area} \times \text{Height}
\]
**Max's Carton:**
- Base Area = 12 square inches
- Height = 6 inches
\[
\text{Volume of Max's carton} = 12 \, \text{in}^2 \times 6 \, \text{in} = 72 \, \text{in}^3
\]
**Tucker's Carton:**
- Base Area = 10 square inches
- Height = 7 inches
\[
\text{Volume of Tucker's carton} = 10 \, \text{in}^2 \times 7 \, \text{in} = 70 \, \text{in}^3
\]
**Difference in Volume:**
Now, we can find how much more volume Max's carton has than Tucker's:
\[
\text{Difference} = \text{Volume of Max's carton} - \text{Volume of Tucker's carton}
\]
\[
\text{Difference} = 72 \, \text{in}^3 - 70 \, \text{in}^3 = 2 \, \text{in}^3
\]
Thus, Max's carton has **2 cubic inches** more volume than Tucker's carton.
\[
\text{Volume} = \text{Base Area} \times \text{Height}
\]
**Max's Carton:**
- Base Area = 12 square inches
- Height = 6 inches
\[
\text{Volume of Max's carton} = 12 \, \text{in}^2 \times 6 \, \text{in} = 72 \, \text{in}^3
\]
**Tucker's Carton:**
- Base Area = 10 square inches
- Height = 7 inches
\[
\text{Volume of Tucker's carton} = 10 \, \text{in}^2 \times 7 \, \text{in} = 70 \, \text{in}^3
\]
**Difference in Volume:**
Now, we can find how much more volume Max's carton has than Tucker's:
\[
\text{Difference} = \text{Volume of Max's carton} - \text{Volume of Tucker's carton}
\]
\[
\text{Difference} = 72 \, \text{in}^3 - 70 \, \text{in}^3 = 2 \, \text{in}^3
\]
Thus, Max's carton has **2 cubic inches** more volume than Tucker's carton.