No.
Final energy = initial energy
final energy is KE only, so 1/2 mvf^2
initial energy is KE and PE, so 1/2m*5^2 + mg50
1/2 mvf^2= 1/2 m 5^2 + mg50 now solve.
A 50kg skier pushes off the top of a hill with an initial speed of 5m/s. Neglect friction. How fast will he be moving after dropping 20m in elevation?
I was wondering if i did this problem correct.
PE + KE_f = KE_i
mgh +1/2mv_f^2 =1/2mv_i^2
50(10)(20) + 1/2 (50)v_f^2 = 1/2(50)(5)^2
10000+ 25v_f^2 =625
25v_f^2=-9375
vf^2=-375
vf=19.36 m/s
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