To determine which charge would be most strongly attracted to object A (which has a charge of -1 Coulomb), we need to consider Coulomb's Law. According to Coulomb's Law, the force between two charges is given by:
\[ F = k \frac{|q_1 q_2|}{r^2} \]
where:
- \( F \) is the magnitude of the force between the charges,
- \( k \) is Coulomb's constant,
- \( q_1 \) and \( q_2 \) are the amounts of the two charges,
- \( r \) is the distance between the charges.
Attraction occurs between charges of opposite signs. This means that charge A (-1 C) will attract positive charges and repel negative charges.
Let's evaluate the options:
- -1 C: This charge is the same sign as object A, so it will be repelled.
- +2 C: This charge is opposite in sign, so it will be attracted. The force will be proportional to \( |-1 \times +2| = 2 \).
- +1 C: This charge is also opposite in sign, so it will be attracted. The force will be proportional to \( |-1 \times +1| = 1 \).
- -2 C: This charge is of the same sign as object A, so it will be repelled.
The charge that is most strongly attracted to object A is +2 C, because it produces the greatest force of attraction (magnitude 2) compared to the other charges.
Thus, the answer is: +2 C.