•x In the inequality, what are all the possible values of x?

Question

2(x + 12) - 16≤8

A
x < 0

B
X≤0
《×
C
x ≥0

D
x ≤ 1

Answer 1

To solve the inequality \(2(x + 12) - 16 \leq 8\), we can follow these steps:

1. Distribute the 2: \[ 2x + 24 - 16 \leq 8 \]

2. Simplify the left side: \[ 2x + 8 \leq 8 \]

3. Subtract 8 from both sides: \[ 2x \leq 0 \]

4. Divide both sides by 2: \[ x \leq 0 \]

So the solution to the inequality is \(x \leq 0\).

The answer corresponds to option B: \(x \leq 0\).