To solve this problem, we need to determine the probabilities for the events A and B, as well as whether they are independent.
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Determine \( P(A \text{ and } B) \):
- Event A (choosing a red card): There are 26 red cards in total (13 diamonds + 13 hearts).
- Event B (choosing an ace): There are 4 aces in total (one for each suit).
- The only red aces are the Ace of Diamonds and the Ace of Hearts, so there are 2 outcomes that satisfy both events A and B.
Therefore, \[ P(A \text{ and } B) = \frac{\text{Number of outcomes in } A \text{ and } B}{\text{Total number of outcomes}} = \frac{2}{52} = \frac{1}{26} \]
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Determine \( P(A) \):
- The probability of event A (choosing a red card): \[ P(A) = \frac{\text{Number of red cards}}{\text{Total number of cards}} = \frac{26}{52} = \frac{1}{2} \]
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Determine \( P(B) \):
- The probability of event B (choosing an ace): \[ P(B) = \frac{\text{Number of aces}}{\text{Total number of cards}} = \frac{4}{52} = \frac{1}{13} \]
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Determine if events A and B are independent:
- Two events A and B are independent if \[ P(A \text{ and } B) = P(A) \cdot P(B) \]
- We calculated:
- \( P(A \text{ and } B) = \frac{1}{26} \)
- \( P(A) \cdot P(B) = \frac{1}{2} \cdot \frac{1}{13} = \frac{1}{26} \)
Since \( P(A \text{ and } B) = P(A) \cdot P(B) \), we conclude that events A and B are independent.
Final Answers:
- \( P(A \text{ and } B) = \frac{1}{26} \)
- \( P(A) = \frac{1}{2} \)
- \( P(B) = \frac{1}{13} \)
- Events A and B are independent (enter 2).
So, the responses are:
- \( P(A \text{ and } B) = \frac{1}{26} \)
- \( P(A) = \frac{1}{2} \)
- \( P(B) = \frac{1}{13} \)
- Enter 2 for independence.