Asked by Lorena
An electron is released from rest at a distance of 9 cm from a proton. How fast will the electron be moving when it is 3 cm from the proton?
Answers
Answered by
bobpursley
At nine cm, the potential V=kq/.09
at three cm, the potential V=kq/.03
energy gained by electron=differencePotential*e
1/2 mv^2=kq(1/.03-1/.09)e
solve for v
at three cm, the potential V=kq/.03
energy gained by electron=differencePotential*e
1/2 mv^2=kq(1/.03-1/.09)e
solve for v
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