To answer your questions, let's break down each part.
Part 1: Probability of Choosing Model B with a Garage
There are 6 house models (A, B, C, D, E, and F) and for each model, a client can choose between a garage or a carport.
Thus, the total options available for a client are:
- Model A + Garage
- Model A + Carport
- Model B + Garage
- Model B + Carport
- Model C + Garage
- Model C + Carport
- Model D + Garage
- Model D + Carport
- Model E + Garage
- Model E + Carport
- Model F + Garage
- Model F + Carport
So, there are a total of \(6 \text{ models} \times 2 \text{ options} = 12 \text{ total choices}\).
The specific choice of Model B with a garage is just 1 of these options.
Therefore, the probability of a client choosing Model B with a garage is:
\[ P(\text{Model B with Garage}) = \frac{1}{12} \]
From the responses you provided, the correct answer is:
112 (1 over 12)
Part 2: Correct Chart for Possible Choices
To summarize, a client has the following combinations to choose from:
- Model A + Garage
- Model A + Carport
- Model B + Garage
- Model B + Carport
- Model C + Garage
- Model C + Carport
- Model D + Garage
- Model D + Carport
- Model E + Garage
- Model E + Carport
- Model F + Garage
- Model F + Carport
The chart that correctly displays all the possible choices for a client when selecting a new home must include each house model combined with both options (Garage and Carport).
From the answers provided, the correct chart is:
Possible Choices
Model A + garage Model A + carport
Model B + garage Model B + carport
Model C + garage Model C + carport
Model D + garage Model D + carport
Model E + garage Model E + carport
Model F + garage Model F + carport
This chart lists all the combinations, satisfying the requirement for displaying all possible choices.