To find the theoretical probability of landing on the letter L, we first need to determine the total number of possible outcomes and how many of those outcomes correspond to the letter L.
From the provided information:
- C = 2 times
- L = 3 times
- E = 1 time
- A = 2 times
- N = 2 times
The total results after 10 spins is: 2 (C) + 3 (L) + 1 (E) + 2 (A) + 2 (N) = 10.
Now, the theoretical probability of landing on L can be calculated like this: since L was one of the results possible when the spinner was spun, if we assume each letter has an equal chance, the total number of possible outcomes based on the number of letters on the spinner is as follows.
Assuming there are 5 letters on the spinner (C, L, E, A, N), the theoretical probability of L would be:
- There is 1 L out of 5 possible outcomes.
So, the theoretical probability of landing on the letter L is: \[ P(L) = \frac{1}{5} = 0.2 = \frac{2}{10} = \text{2 tenths}. \]
Answer for Part 1: 210
(2 tenths)
Part 2:
Now, let's compare Bronwyn's experimental probability of landing on L versus the theoretical probability.
From the tally:
- L was landed on 3 times out of 10 total spins, so the experimental probability is: \[ P(L) = \frac{3}{10} = 0.3. \]
Now, let's fill in the blank for Part 2:
Bronwyn's experimental probability of spinning the letter L is greater than the theoretical probability of spinning the letter L.
Responses for Part 2:
Bronwyn's experimental probability of spinning the letter L is greater than the theoretical probability of spinning the letter L.