Question

Car moving down road accelerates at uniform rate 2.8 m/s/s for 4.63 s to reach a speed of 106.7 m/s.

1) How fast was the car initially moving?
2) What distance did it travel during the a/c/c.?

Answers

bobpursley
This is straightforward stuff...

vf= vi + a*t solve for vi
d= vi*t + 1/2 a t^2

Related Questions