Three numbers whose sum is 15 are in an arithmetic progression. The product of the 1st two numbers is 2 more than the 3rd. Find the three numbers.

Answer 1

Designate the three numbers, in order as x, y and z.

x<y<z

xy = z +2 or xy - 2 = z

x + y + z = 15

x = 2, y = 5, z = 8