Find the area.

a = [?]cm²
5 cm, 27 cm and 19 cm
Shape: Trapezoid
Area of a trapezoid: (B¹ + B²)/2 x H

1 answer

To find the area of the trapezoid, we need the lengths of the two bases (B¹ and B²) and the height (H).

From the dimensions you've given (5 cm, 27 cm, and 19 cm), we can assume:

  • Base 1 (B¹) = 27 cm
  • Base 2 (B²) = 5 cm
  • Height (H) = 19 cm

Now we can use the formula for the area of a trapezoid:

\[ \text{Area} = \frac{(B^1 + B^2)}{2} \times H \]

Substituting the values:

\[ \text{Area} = \frac{(27 , \text{cm} + 5 , \text{cm})}{2} \times 19 , \text{cm} \]

First, calculate \(B^1 + B^2\):

\[ 27 , \text{cm} + 5 , \text{cm} = 32 , \text{cm} \]

Now, plug it back into the area formula:

\[ \text{Area} = \frac{32 , \text{cm}}{2} \times 19 , \text{cm} = 16 , \text{cm} \times 19 , \text{cm} \]

Now, calculate:

\[ 16 \times 19 = 304 \]

Thus, the area \(a\) of the trapezoid is:

\[ a = 304 , \text{cm}² \]