Question

Question

Use the tables to answer the question.

Simon’s Results

This table shows the number of white and red balls Simon selected from Bowl A and Bowl B.
Number of White Balls Selected Number of Red Balls Selected
Bowl A 5 15
Bowl B 16 4
Clark’s Results

This table shows the number of white and red balls Clark selected from Bowl A and Bowl B.
Number of White Balls Selected Number of Red Balls Selected
Bowl A 45 55
Bowl B 60 40
Bowls A and B contain a number of white and red balls. Simon and Clark repeatedly selected a ball from both bowls and recorded the results in a table. Whose results will give you a better indication about the proportion of white and red balls in each bowl? Explain your answer.

(1 point)
Responses

Clark’s experiment. He conducted a greater number of trials than Simon.
Clark’s experiment. He conducted a greater number of trials than Simon.

Simon’s experiment. He conducted a greater number of trials than Clark.
Simon’s experiment. He conducted a greater number of trials than Clark.

Neither; they conducted the same number of trials.
Neither; they conducted the same number of trials.

Both results can be used, as they performed the experiment at random.

Answer 1

To determine whose results give a better indication of the proportion of white and red balls in each bowl, we can look at the total number of trials (i.e., the total number of balls selected) each person conducted.

• Simon's Results:

  • Bowl A: 5 white + 15 red = 20 total
  • Bowl B: 16 white + 4 red = 20 total
  • Total Trials for Simon = 20 + 20 = 40

• Clark's Results:

  • Bowl A: 45 white + 55 red = 100 total
  • Bowl B: 60 white + 40 red = 100 total
  • Total Trials for Clark = 100 + 100 = 200

Clark conducted a greater number of trials (200) compared to Simon (40). The larger sample size reduces the variability and gives a more accurate estimate of the proportions of white and red balls in each bowl.

Therefore, the answer is:

Clark’s experiment. He conducted a greater number of trials than Simon.