To determine the mRNA codons for the albino cat, we first need to transcribe the given DNA sequence (CCT-CCT-CTG-CTG) into its corresponding mRNA sequence.
In DNA, the base pairs are transcribed to mRNA as follows:
- Adenine (A) in DNA pairs with Uracil (U) in mRNA
- Thymine (T) in DNA pairs with Adenine (A) in mRNA
- Cytosine (C) in DNA pairs with Guanine (G) in mRNA
- Guanine (G) in DNA pairs with Cytosine (C) in mRNA
Now, let's transcribe the DNA sequence for the albino cat:
- CCT → GGA
- CCT → GGA
- CTG → CAG
- CTG → CAG
So, the mRNA codons would be:
- CCT → GGA
- CCT → GGA
- CTG → CAG
- CTG → CAG
Now, we can see that none of the choices exactly match this sequence. However, it looks like the options mix up the transcription a bit, but let's check one more time if there's a commonly made mistake in identifying codons (for instance, reading the codons incorrectly).
Given the listed answers, let’s check them:
A. GGA GGA GAC GAC B. GGG AGG AGA CGA C. CCU CCU AUG AUG D. GGU GGU GUC GUC
The best match for the expected sequence (GGA, GGA, CAG, CAG) is not present as an exact answer. However, checking the options can lead us to think perhaps one closer to even the errors made or common mutations.
Since GGA is a common transcription base in terms of phenotype appearance (white cats), among the available choices, A. GGA GGA GAC GAC has a logical connection, even if the second half diverges (the A or G while CAG suggests perhaps a mutation).
So based on this analysis:
The best answer is A. GGA GGA GAC GAC.