find, in cm2, the area of material required for a lampshade in the form of a frustum of a cone of which the top and bottom diameters are 20cm and 30cm respictively, and the vertical height is 12 cm

1 answer

To find the area of material required for the lampshade in the form of a frustum of a cone, we can use the formula for the lateral surface area of a frustum of a cone:

\[ A = \pi (r_1 + r_2) l \]

where:

  • \( A \) is the lateral surface area,
  • \( r_1 \) is the radius of the smaller base (top),
  • \( r_2 \) is the radius of the larger base (bottom),
  • \( l \) is the slant height of the frustum.

First, we need to find the radii of the frustum bases:

  • The diameter of the top \( (d_1) = 20 , \text{cm} \) gives \( r_1 = \frac{d_1}{2} = 10 , \text{cm} \).
  • The diameter of the bottom \( (d_2) = 30 , \text{cm} \) gives \( r_2 = \frac{d_2}{2} = 15 , \text{cm} \).

Now, we will find the slant height \( l \) of the frustum. The vertical height \( h \) is given as 12 cm. We can calculate the slant height using the Pythagorean theorem, where \( l \) is the hypotenuse:

\[ l = \sqrt{(r_2 - r_1)^2 + h^2} \]

Substituting the values:

\[ l = \sqrt{(15 - 10)^2 + 12^2} = \sqrt{5^2 + 12^2} = \sqrt{25 + 144} = \sqrt{169} = 13 , \text{cm} \]

Now, we can substitute \( r_1 \), \( r_2 \), and \( l \) into the area formula:

\[ A = \pi (r_1 + r_2) l = \pi (10 + 15) \cdot 13 \] \[ A = \pi \cdot 25 \cdot 13 = 325\pi , \text{cm}^2 \]

To express the area in numerical form:

\[ A \approx 325 \cdot 3.14 \approx 1021.5 , \text{cm}^2 \]

Thus, the area of material required for the lampshade is approximately:

\[ \boxed{1021.5 , \text{cm}^2} \]