Question

Balance the following chemical equation and classify them into their different class .
A. FeCl3 (aq) + KOH (aq) = Fe (OH)3 (s) +KCI (aq)

Answer 1

To balance the chemical equation and classify it into its respective reaction class, let's first look at the unbalanced equation:

**Unbalanced equation:**
\[ \text{FeCl}_3 (aq) + \text{KOH} (aq) \rightarrow \text{Fe(OH)}_3 (s) + \text{KCl} (aq) \]

### Step 1: Balancing the equation

1. Count the number of atoms of each element on both sides.
2. Balance the equation.

**Reactants:**
- Fe: 1 (from FeCl3)
- Cl: 3 (from FeCl3)
- K: 1 (from KOH)
- O: 1 (from KOH)
- H: 1 (from KOH)

**Products:**
- Fe: 1 (from Fe(OH)3)
- Cl: 1 (from KCl)
- K: 1 (from KCl)
- O: 3 (from Fe(OH)3)
- H: 3 (from Fe(OH)3)

### Balancing

To balance the equation, we need to account for the chlorine and hydroxide ions. We need 3 KCl to balance the chlorines, and thus we will also need 3 KOH:

**Balanced Equation:**
\[ \text{FeCl}_3 (aq) + 3 \text{KOH} (aq) \rightarrow \text{Fe(OH)}_3 (s) + 3 \text{KCl} (aq) \]

### Step 2: Classifying the reaction

This chemical reaction can be classified as a **double displacement reaction** (also known as a double replacement or metathesis reaction). In this type of reaction, the cations and anions of two different compounds swap places, forming two new compounds.

### Summary

- **Balanced Equation:**
\[ \text{FeCl}_3 (aq) + 3 \text{KOH} (aq) \rightarrow \text{Fe(OH)}_3 (s) + 3 \text{KCl} (aq) \]

- **Class of Reaction:** Double displacement reaction.