A = F/m
A = (F1+F2)/4
F1+F2 = 6 i - 14 j as you said
so
A = (3/2) i - (7/2) j
sure if you want the magnitude go ahead and use 12.5/4 but it just said find the acceleration which is the vector A
A 4kg object is subjected to two forces, F1=2Ni-3Nj, and F2=4Ni-11Nj. The object is at rest at the origin at t=0.
What is the objects acceleration? I know you use F=m*a
Do you add the two F vectors together & take the square root to find the sum of F?
ex: Fnet=6Ni-14Nj & then sqrt(6^2+14^2)=12.5N
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it looks right to me. just plug in 12.5N and 4kg into the formula and solve for acceleration.
Thanks guys!
How did you manage to get 12.5N? because sqrt(6^2+14^2) = 15.2 N. Unless you just got the numbers mixed up
0 answers