A stationary source produces a sound wave at a frequency of 100 Hz. The wave travels at 1125 feet per second. A car is moving toward the sound source at a speed of 200 feet per second.

What is the wavelength of the stationary sound source and the wavelength that a person in the car perceives?

(1 point)
Responses

wavelength of the stationary source: 9.25 ft; perceived wavelength: 11.25 ft
wavelength of the stationary source: 9.25 ft; perceived wavelength: 11.25 ft

wavelength of the stationary source: 11.25 ft; perceived wavelength: 13.25 ft
wavelength of the stationary source: 11.25 ft; perceived wavelength: 13.25 ft

wavelength of the stationary source: 11.25 ft; perceived wavelength: 9.25 ft
wavelength of the stationary source: 11.25 ft; perceived wavelength: 9.25 ft

wavelength of the stationary source: 13.25 ft; perceived wavelength: 11.25 ft

1 answer

To find the wavelength of the stationary sound source and the perceived wavelength by an observer in the moving car, we can use the following formulas.

  1. Wavelength (\(\lambda\)) is calculated using the formula: \[ \lambda = \frac{v}{f} \] where \(v\) is the speed of the wave and \(f\) is the frequency.

  2. For a person in the moving car, the perceived frequency (\(f'\)) can be calculated using the Doppler effect formula. Since the car is moving toward the sound source, the formula is given by: \[ f' = f \times \frac{v + v_o}{v} \] where:

    • \(f\) is the frequency of the source (100 Hz),
    • \(v\) is the speed of sound (1125 feet/second),
    • \(v_o\) is the speed of the observer (the car) (200 feet/second).
  3. The perceived wavelength \(\lambda'\) can then be calculated using the same wavelength formula using the perceived frequency: \[ \lambda' = \frac{v}{f'} \]

Step 1: Calculate the wavelength of the stationary source

Using the given frequency and speed of the sound: \[ \lambda = \frac{1125 \text{ ft/s}}{100 \text{ Hz}} = 11.25 \text{ ft} \]

Step 2: Calculate the perceived frequency for the moving observer

Using the Doppler effect formula: \[ f' = 100 \text{ Hz} \times \frac{1125 + 200}{1125} = 100 \text{ Hz} \times \frac{1325}{1125} \] Calculating \(f'\): \[ f' \approx 100 \text{ Hz} \times 1.17778 \approx 117.78 \text{ Hz} \]

Step 3: Calculate the perceived wavelength

Now, we can calculate the perceived wavelength using the perceived frequency: \[ \lambda' = \frac{1125 \text{ ft/s}}{117.78 \text{ Hz}} \approx 9.55 \text{ ft} \]

Conclusion

Therefore, the wavelengths are:

  • Wavelength of the stationary sound source: 11.25 ft
  • Perceived wavelength by the car: approximately 9.55 ft

The closest response given the options is:

  • wavelength of the stationary source: 11.25 ft; perceived wavelength: 9.25 ft

Thus, the answer is: wavelength of the stationary sound source: 11.25 ft; perceived wavelength: 9.25 ft.