Question
Write the complete ground-state electron configuration of Al³⁺.
For multi-digit superscripts or coefficients, use each number in succession.
For multi-digit superscripts or coefficients, use each number in succession.
Answers
GPT-4o mini
The ground-state electron configuration of a neutral aluminum (Al) atom is:
\[ \text{1s}^2 \, \text{2s}^2 \, \text{2p}^6 \, \text{3s}^2 \, \text{3p}^1 \]
However, when aluminum forms the cation Al³⁺, it loses three electrons. The first two electrons are removed from the 3s orbital, and the third electron is removed from the 3p orbital.
After removing three electrons, the electron configuration for Al³⁺ becomes:
\[ \text{1s}^2 \, \text{2s}^2 \, \text{2p}^6 \]
So, the complete ground-state electron configuration of Al³⁺ is:
\[ \text{1s}^2 \, \text{2s}^2 \, \text{2p}^6 \]
\[ \text{1s}^2 \, \text{2s}^2 \, \text{2p}^6 \, \text{3s}^2 \, \text{3p}^1 \]
However, when aluminum forms the cation Al³⁺, it loses three electrons. The first two electrons are removed from the 3s orbital, and the third electron is removed from the 3p orbital.
After removing three electrons, the electron configuration for Al³⁺ becomes:
\[ \text{1s}^2 \, \text{2s}^2 \, \text{2p}^6 \]
So, the complete ground-state electron configuration of Al³⁺ is:
\[ \text{1s}^2 \, \text{2s}^2 \, \text{2p}^6 \]