Asked by bloozoo
Karen asked some eighth graders whether they would prefer to take yearbook or photography as an elective in high school. This table shows some of the results.
Complete the table.
Yearbook Photography Total
Girls
18 31
Boys 12
26
Total 25
What percentage of students would prefer to take photography? Round your answer to the nearest tenth of a percent.
%
Complete the table.
Yearbook Photography Total
Girls
18 31
Boys 12
26
Total 25
What percentage of students would prefer to take photography? Round your answer to the nearest tenth of a percent.
%
Answers
Answered by
GPT-4o mini
Let's first fill in the missing values in the table based on the data given.
We know the totals for the rows and columns:
1. For Girls:
- Yearbook: 18
- Photography: \(31\) (given)
The total number of girls is \(18 + 31 = 49\).
2. For Boys:
- Yearbook: \(12\) (given)
- Photography: (unknown)
We know the total for Boys is \(26\), so:
\[
12 + \text{Photography} = 26 \implies \text{Photography} = 26 - 12 = 14.
\]
Now we can fill in the table:
| | Yearbook | Photography | Total |
|-----------|----------|-------------|-------|
| Girls | 18 | 31 | 49 |
| Boys | 12 | 14 | 26 |
| Total | 30 | 45 | 75 |
Now we find the total number of students:
- Total number of students = Total girls + Total boys = 49 + 26 = 75.
Next, we need to find the total number of students preferring Photography:
- Total Photography = Girls Photography + Boys Photography = 31 + 14 = 45.
Now, we can calculate the percentage of students who would prefer Photography:
\[
\text{Percentage of students preferring Photography} = \left( \frac{\text{Total Photography}}{\text{Total students}} \right) \times 100 = \left( \frac{45}{75} \right) \times 100.
\]
\[
= 0.6 \times 100 = 60\%.
\]
Therefore, the percentage of students who would prefer to take photography is **60.0%** (rounded to the nearest tenth of a percent).
We know the totals for the rows and columns:
1. For Girls:
- Yearbook: 18
- Photography: \(31\) (given)
The total number of girls is \(18 + 31 = 49\).
2. For Boys:
- Yearbook: \(12\) (given)
- Photography: (unknown)
We know the total for Boys is \(26\), so:
\[
12 + \text{Photography} = 26 \implies \text{Photography} = 26 - 12 = 14.
\]
Now we can fill in the table:
| | Yearbook | Photography | Total |
|-----------|----------|-------------|-------|
| Girls | 18 | 31 | 49 |
| Boys | 12 | 14 | 26 |
| Total | 30 | 45 | 75 |
Now we find the total number of students:
- Total number of students = Total girls + Total boys = 49 + 26 = 75.
Next, we need to find the total number of students preferring Photography:
- Total Photography = Girls Photography + Boys Photography = 31 + 14 = 45.
Now, we can calculate the percentage of students who would prefer Photography:
\[
\text{Percentage of students preferring Photography} = \left( \frac{\text{Total Photography}}{\text{Total students}} \right) \times 100 = \left( \frac{45}{75} \right) \times 100.
\]
\[
= 0.6 \times 100 = 60\%.
\]
Therefore, the percentage of students who would prefer to take photography is **60.0%** (rounded to the nearest tenth of a percent).