Question
150 grams of calcium sulfate were used to make a 500.0 ml solution. What is the concentration of this solution?
Answers
GPT-4o mini
To find the concentration of the solution, we need to calculate the number of moles of calcium sulfate (CaSO₄) and then determine the molarity (concentration) of the solution.
1. **Calculate the molar mass of calcium sulfate (CaSO₄):**
- Calcium (Ca): 40.08 g/mol
- Sulfur (S): 32.07 g/mol
- Oxygen (O): 16.00 g/mol × 4 = 64.00 g/mol
Molar mass of CaSO₄ = 40.08 g/mol + 32.07 g/mol + 64.00 g/mol = 136.15 g/mol
2. **Calculate the number of moles of CaSO₄ in 150 grams:**
\[
\text{Number of moles} = \frac{\text{mass}}{\text{molar mass}} = \frac{150 \, \text{g}}{136.15 \, \text{g/mol}} \approx 1.101 \, \text{mol}
\]
3. **Calculate the concentration (molarity) of the solution:**
- Volume of the solution = 500.0 mL = 0.500 L
\[
\text{Concentration (M)} = \frac{\text{number of moles}}{\text{volume in liters}} = \frac{1.101 \, \text{mol}}{0.500 \, \text{L}} \approx 2.202 \, \text{M}
\]
Thus, the concentration of the calcium sulfate solution is approximately **2.20 M**.
1. **Calculate the molar mass of calcium sulfate (CaSO₄):**
- Calcium (Ca): 40.08 g/mol
- Sulfur (S): 32.07 g/mol
- Oxygen (O): 16.00 g/mol × 4 = 64.00 g/mol
Molar mass of CaSO₄ = 40.08 g/mol + 32.07 g/mol + 64.00 g/mol = 136.15 g/mol
2. **Calculate the number of moles of CaSO₄ in 150 grams:**
\[
\text{Number of moles} = \frac{\text{mass}}{\text{molar mass}} = \frac{150 \, \text{g}}{136.15 \, \text{g/mol}} \approx 1.101 \, \text{mol}
\]
3. **Calculate the concentration (molarity) of the solution:**
- Volume of the solution = 500.0 mL = 0.500 L
\[
\text{Concentration (M)} = \frac{\text{number of moles}}{\text{volume in liters}} = \frac{1.101 \, \text{mol}}{0.500 \, \text{L}} \approx 2.202 \, \text{M}
\]
Thus, the concentration of the calcium sulfate solution is approximately **2.20 M**.