How many solutions can be found for the linear equation?



10(x+6)/2 - 9 = (15x+1)/3 - 8
Responses
A no solutions
B one solution
C two solutions
D infinite many solutions

1 answer

To determine the number of solutions for the linear equation

\[ \frac{10(x+6)}{2} - 9 = \frac{15x+1}{3} - 8, \]

we can start by simplifying both sides of the equation.

First, simplify the left side:

\[ \frac{10(x+6)}{2} = 5(x+6) = 5x + 30. \] Thus, the left side becomes: \[ 5x + 30 - 9 = 5x + 21. \]

Now simplify the right side:

\[ \frac{15x+1}{3} = 5x + \frac{1}{3}. \] Thus, the right side becomes: \[ 5x + \frac{1}{3} - 8 = 5x + \frac{1}{3} - \frac{24}{3} = 5x - \frac{23}{3}. \]

Now we have the simplified equation:

\[ 5x + 21 = 5x - \frac{23}{3}. \]

Next, we can subtract \(5x\) from both sides:

\[ 21 = -\frac{23}{3}. \]

Now we need to determine if this statement is true. The statement \(21 = -\frac{23}{3}\) is false, because \(21\) is a positive integer while \(-\frac{23}{3}\) is a negative fraction.

Since the equation results in a false statement, it indicates that there are no values of \(x\) that can satisfy the original equation.

Thus, the answer is:

A) no solutions.