Question

Arrange the following compounds from the least soluble to most soluble at 10oC. 1. KCl 2. NaCl 3. NH3 4. SO2 5. KClO3

Answer 1

To arrange the compounds from least soluble to most soluble at 10°C, we need to consider their solubilities in water at that temperature. Here’s a general idea of the solubilities of these compounds:

1. **SO2 (sulfur dioxide)** - It is soluble in water but not to a very great extent compared to the ionic compounds.
2. **NH3 (ammonia)** - It is highly soluble in water; however, it is a gas and can be affected by temperature and pressure.
3. **KCl (potassium chloride)** - It has good solubility in water (about 31 g/100 mL at 10°C).
4. **NaCl (sodium chloride)** - It is also soluble in water but typically has a slightly higher solubility than KCl (about 35.7 g/100 mL at 10°C).
5. **KClO3 (potassium chlorate)** - It is even more soluble than KCl and NaCl (about 7 g/100 mL at 10°C).

Based on the general trends and specific solubility data, we can order the compounds from least soluble to most soluble as follows:

1. **SO2**
2. **NH3**
3. **KCl**
4. **NaCl**
5. **KClO3**

So, the final arrangement from least soluble to most soluble at 10°C is:

**SO2 < NH3 < KCl < NaCl < KClO3**