To factor the quadratic expression \( d^2 + 6d - 16 \), we need to find two numbers that multiply to \(-16\) (the constant term) and add up to \(6\) (the coefficient of the \(d\) term).
The numbers that satisfy these conditions are \(8\) and \(-2\) because:
- \(8 \times (-2) = -16\)
- \(8 + (-2) = 6\)
Using these numbers, we can write the expression in factored form:
\[ d^2 + 6d - 16 = (d + 8)(d - 2) \]
Thus, the factored form of \(d^2 + 6d - 16\) is \((d + 8)(d - 2)\).