-4 squareroot 3 + 4 squareroot 108

1 answer

To simplify the expression \(-4\sqrt{3} + 4\sqrt{108}\), let's first simplify \(\sqrt{108}\).

We start by breaking down 108:

\[ 108 = 36 \times 3 = 6^2 \times 3 \]

Thus, we can simplify:

\[ \sqrt{108} = \sqrt{36 \times 3} = \sqrt{36} \cdot \sqrt{3} = 6\sqrt{3} \]

Now we can substitute \(\sqrt{108}\) back into the original expression:

\[ -4\sqrt{3} + 4\sqrt{108} = -4\sqrt{3} + 4(6\sqrt{3}) \]

Now multiply \(4\) by \(6\sqrt{3}\):

\[ 4(6\sqrt{3}) = 24\sqrt{3} \]

Now the expression becomes:

\[ -4\sqrt{3} + 24\sqrt{3} \]

Now combine like terms:

\[ (-4 + 24)\sqrt{3} = 20\sqrt{3} \]

Thus, the simplified expression is:

\[ \boxed{20\sqrt{3}} \]