According to Ohm's Law (V = IR), if the voltage (V) remains constant and the current (I) is halved, the resistance (R) must increase to maintain the relationship.
Let's analyze the situation:
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If the current is halved (I/2), and the voltage remains constant, we can rewrite Ohm's Law as: \[ V = R \cdot (I/2) \]
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Rearranging gives us: \[ R = V / (I/2) = (2V) / I \]
This implies that if I is halved, R must double to maintain the same voltage.
Therefore, the correct response is:
The resistance is doubled.