letter is to be picked at random from the English alphabet. If each letter is equally likely to be selected, what is the probability of selecting a consonant? Consonants are letters except for a, e, i, o, and u. Write your answer in the simplest form of fraction.(1 point)

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1 answer

The English alphabet consists of 26 letters. The vowels in the English alphabet are a, e, i, o, and u, which means there are 5 vowels.

To find the number of consonants, we subtract the number of vowels from the total number of letters:

\[ \text{Number of consonants} = 26 - 5 = 21 \]

Now we can calculate the probability of selecting a consonant. The probability \( P \) is calculated as the number of favorable outcomes (selecting a consonant) divided by the total number of possible outcomes (selecting any letter):

\[ P(\text{consonant}) = \frac{\text{Number of consonants}}{\text{Total letters}} = \frac{21}{26} \]

Since 21 and 26 have no common factors other than 1, this fraction is already in its simplest form.

Thus, the probability of selecting a consonant is

\[ \frac{21}{26} \]