The equation that best models the linearized data for a particular data set is log y equals 0.75821 x plus 0.03442. Find the approximate value of y when x = 4. Round your answer to the nearest whole number.

(1 point)
Responses

3
3

25
25

1,168
1,168

62,034

1 answer

To find the approximate value of \( y \) when \( x = 4 \), we need to first calculate \( \log y \) using the equation provided:

\[ \log y = 0.75821 \cdot x + 0.03442 \]

Substituting \( x = 4 \):

\[ \log y = 0.75821 \cdot 4 + 0.03442 \]

Calculating \( 0.75821 \cdot 4 \):

\[ 0.75821 \cdot 4 = 3.03284 \]

Now we add \( 0.03442 \):

\[ \log y = 3.03284 + 0.03442 = 3.06726 \]

Next, we convert from the logarithmic form to the original form \( y \):

\[ y = 10^{\log y} = 10^{3.06726} \]

Using a calculator to compute \( 10^{3.06726} \):

\[ y \approx 1168.2 \]

Rounding this to the nearest whole number, we find:

\[ y \approx 1168 \]

Therefore, the approximate value of \( y \) when \( x = 4 \) is:

1,168