Ancilla applies a force of 200 N [E] horizontally to pull a 38 kg sled across the snow at a constant velocity for 200 m.

(a) What is the magnitude of the normal force on the sled?

1 answer

To determine the magnitude of the normal force acting on the sled, we need to consider the forces acting on the sled in the vertical direction.

  1. Weight of the sled (W): The weight can be calculated using the equation: \[ W = m \cdot g \] where:

    • \( m = 38 , \text{kg} \) (mass of the sled)
    • \( g \approx 9.81 , \text{m/s}^2 \) (acceleration due to gravity)

    So, the weight of the sled is: \[ W = 38 , \text{kg} \cdot 9.81 , \text{m/s}^2 \approx 372.78 , \text{N} \]

  2. Vertical forces acting on the sled: The sled is moving horizontally at a constant velocity, which means the net force in the vertical direction must be zero (since there is no vertical acceleration). The forces acting vertically are:

    • The weight of the sled acting downwards (372.78 N)
    • The normal force (N) acting upwards

    Since there are no other vertical forces acting on the sled, we can set up the equation: \[ N - W = 0 \]

    Therefore: \[ N = W \]

  3. Calculating the normal force: Substituting the weight we calculated: \[ N = 372.78 , \text{N} \]

Thus, the magnitude of the normal force on the sled is approximately 372.78 N.