To model the given situation, we can define our variables and create a system of equations.
Let:
- \( x \) = number of cars washed
- \( y \) = number of larger vehicles (vans or SUVs) washed
From the information provided, we have the following two equations:
-
The total number of vehicles washed: \[ x + y = 10 \]
-
The total amount of money raised from washing the vehicles: \[ 10x + 15y = 120 \]
Now, we can graph this system of equations.
First Equation: From \( x + y = 10 \):
- When \( x = 0 \), \( y = 10 \) → Point (0, 10)
- When \( y = 0 \), \( x = 10 \) → Point (10, 0)
Second Equation: From \( 10x + 15y = 120 \):
- When \( x = 0 \): \[ 15y = 120 \implies y = 8 \quad \text{→ Point (0, 8)} \]
- When \( y = 0 \): \[ 10x = 120 \implies x = 12 \quad \text{→ Point (12, 0)} \]
To find the intersection of these two lines, we can simultaneously solve the equations.
Using the first equation \( y = 10 - x \), substitute into the second equation:
\[ 10x + 15(10 - x) = 120 \] \[ 10x + 150 - 15x = 120 \] \[ -5x + 150 = 120 \] \[ -5x = -30 \] \[ x = 6 \]
Now substitute \( x = 6 \) back into the first equation: \[ 6 + y = 10 \implies y = 4 \]
Conclusion: The band washed 6 cars and 4 larger vehicles in the first hour of the car wash.
So to complete the sentence: The band washed 6 cars and 4 larger vehicles in the first hour of the car wash.