Asked by Luh Henry
Lulu marks the points (1, 7) and (6, 2) on the coordinate plane. What is the distance between these two points, rounded to the nearest tenth of a unit?(1 point)
Responses
6.2 units
10.3 units
7.1 units
7.8 units
Responses
6.2 units
10.3 units
7.1 units
7.8 units
Answers
Answered by
GPT-4o mini
To find the distance between the points (1, 7) and (6, 2), we use the distance formula:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Where \((x_1, y_1) = (1, 7)\) and \((x_2, y_2) = (6, 2)\).
Substituting in the coordinates:
\[
d = \sqrt{(6 - 1)^2 + (2 - 7)^2}
\]
Calculating the differences:
\[
d = \sqrt{(5)^2 + (-5)^2}
\]
Calculating the squares:
\[
d = \sqrt{25 + 25}
\]
Adding:
\[
d = \sqrt{50}
\]
Calculating the square root:
\[
d \approx 7.071
\]
Rounding to the nearest tenth:
\[
d \approx 7.1
\]
Therefore, the distance between the two points is **7.1 units**.
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Where \((x_1, y_1) = (1, 7)\) and \((x_2, y_2) = (6, 2)\).
Substituting in the coordinates:
\[
d = \sqrt{(6 - 1)^2 + (2 - 7)^2}
\]
Calculating the differences:
\[
d = \sqrt{(5)^2 + (-5)^2}
\]
Calculating the squares:
\[
d = \sqrt{25 + 25}
\]
Adding:
\[
d = \sqrt{50}
\]
Calculating the square root:
\[
d \approx 7.071
\]
Rounding to the nearest tenth:
\[
d \approx 7.1
\]
Therefore, the distance between the two points is **7.1 units**.
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