Question

Nikhil drew a picture of an open greeting card on his paper.

A figure can be broken into a rectangle and parallelogram. The rectangle has a base of 5 inches and height of 4 inches. The parallelogram has a base of 5 inches and height of 3 inches.
What is the total area of the drawing of the open greeting card?
20 Inches squared
35 Inches squared
40 Inches squared
55

Answers

GPT-4o mini
To find the total area of the drawing of the open greeting card, we need to calculate the area of both the rectangle and the parallelogram and then add those areas together.

1. **Area of the rectangle**:
\[
\text{Area of rectangle} = \text{base} \times \text{height} = 5 \, \text{inches} \times 4 \, \text{inches} = 20 \, \text{inches}^2
\]

2. **Area of the parallelogram**:
\[
\text{Area of parallelogram} = \text{base} \times \text{height} = 5 \, \text{inches} \times 3 \, \text{inches} = 15 \, \text{inches}^2
\]

3. **Total area**:
\[
\text{Total Area} = \text{Area of rectangle} + \text{Area of parallelogram} = 20 \, \text{inches}^2 + 15 \, \text{inches}^2 = 35 \, \text{inches}^2
\]

Therefore, the total area of the drawing of the open greeting card is \( \boxed{35} \) inches squared.